(√x-1)^2=8-√28 ka solve question
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Heya!!
★Answer★
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(√x-1)^2=8-√28
→(√x)^2 - (1)^2 = 8 - √28
→ (√x+1) (√x-1) =8-√28
→x -√x + √x -1 = 8- √28
→ x = 8-1-√28
→ x = 7-√28
→ x = 7 - √2×2×7
→ x = 7 - 2√7
_______________________________
#hope helped
★Answer★
______________________________
(√x-1)^2=8-√28
→(√x)^2 - (1)^2 = 8 - √28
→ (√x+1) (√x-1) =8-√28
→x -√x + √x -1 = 8- √28
→ x = 8-1-√28
→ x = 7-√28
→ x = 7 - √2×2×7
→ x = 7 - 2√7
_______________________________
#hope helped
Bhavanavindamuri:
gr8 answer bestuuuu :)
Answered by
12
the question ’s answer is 7
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