{x+1/2} is a factor of px^2-4px+3
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hey I hope this will help u....
x + 1/2 = 0
x = -1/2
substitute in in the given polynomial
since its factor the value of the polynomial when x is -1/2 is 0.
p(1/2^2)-4p(1/2)+3 = 0
p/4-2p+3 = 0
(p - 8p + 12)/4 = 0
p - 8p+ 12 = 0*4 = 0
-7p + 12 = 0
-7p = -12
p = -12/-7
p = 12/7
pls mark as brainliest
x + 1/2 = 0
x = -1/2
substitute in in the given polynomial
since its factor the value of the polynomial when x is -1/2 is 0.
p(1/2^2)-4p(1/2)+3 = 0
p/4-2p+3 = 0
(p - 8p + 12)/4 = 0
p - 8p+ 12 = 0*4 = 0
-7p + 12 = 0
-7p = -12
p = -12/-7
p = 12/7
pls mark as brainliest
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