X=1/2+root3, y=1/2-root3 find the value of 8xy(x^2+y^2)
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Step-by-step explanation:
x=1/2+√3,. y=1/2-√3
On adding X & Y we get,
X+Y=4
On substructing X & Y we get,
x-y= -2√3
And on multiplying X & Y we get,
x×y=1/(4-3)
=>1
Now come onto the question,
8xy(x^2+y^2)
=>8×1(x+y)^2 -2xy
=>8(4)^2 -2×1
=>126
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