Question

x=1/2-underoot3 find the value of x³-2x²-7x+5 ​

Answer 1

Answer:

2−31=2−31∗2+32+3=22−32+3=12+3=2+3

x³ - 2x² - 7x + 5

(2+ \sqrt{3})^3 - 2(2+ \sqrt{3})^2 - 7(2+ \sqrt{3}) + 5(2+3)3−2(2+3)2−7(2+3)+5

8 + 3 \sqrt{3} + 6 \sqrt{3} (2+ \sqrt{3}) - 2(4+3+4 \sqrt{3}) - 7(2+ \sqrt{3}) + 58+33+63(2+3)−2(4+3+43)−7(2+3)+5

8 + 3 \sqrt{3} + 12 \sqrt{3} + 18 - 14-8 \sqrt{3} - 14-7 \sqrt{3} + 58+33+123+18−14−83−14−73+5

31 + 15 \sqrt{3} - 28-15 \sqrt{3}31+153−28−153