Question

x + 1)² - x = 0 has *
1 point
four real roots
two real roots
no real roots
one real root



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Answer 1

Answer:

(X + 1) square - X = 0

X Square + 2x + 1 - X = 0

X Square + 1 X + 1 = 0

a = 1 , b = 1 , c = 1

b square -4ac = 1 square - 4 × 1 × 1

= 1 - 4

= -3 < 0

therefore this quatractic equation has no real roots