Question

(x+1)^2(x-1)^2
solve???​

Answer 1

[(x+1)(x-1)]² = [x²-1]² = x⁴+1-2x²

I hope this helps you

Answer 2

Answer:

(x+1)²(x-1)²

(x²+x+1)(x²+1-x)

x²(x²+1-x) +x(x²-x+1)+1(x²+1-x)

x*4+x²-x³+x³-x²+x+x²+1-x

x*4+x²+1

${x}^{4} + {x}^{2} + 1 = 0$

is the answer