(x+1)^2-x^2=0 has how many roots
Help me guys
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1
Answer:
Step-by-step explanation:
On solving
(x+1)^2-x^2=0
=x^2+1+2x-x^2
=2x+1
as it is a linear polynomial i has only one root which is
2x+1=0
2x=-1
x=-1/2
Answered by
1
Step-by-step explanation:
it has only one zero
hope you will understand
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