Question

(x-1)² + (x-2)² + (x-3)² = 0 has n real roots, then what will be the value of n
a) 1
b) 2
c) 0

please answer it with solution ​

Answer 1

Answer:

0

Step-by-step explanation:

equation becomes :-

$3 {x }^{2} - 12x + 14$

D is negative :--

$\sqrt{ - 24}$

therefore it has complex solutions I. e real solutions don't exist...

OTHER METHOD

ATQ

x has to be equal to 1,2,3 at the same time for it to be zero this leads to contradiction therefore no real solution exists

FOLLOW AND MARK AS BRAINLIEST

Answer 2

Step-by-step explanation:

Ohhk thank you This helps too much