Question

(x-1)²+(x-2)²+(x-3)²=0 let us determine the number of real roots​

Answer 1

$(x - 1) {}^{2} + (x - 2) {}^{2} + (x - 3) {}^{2} = 0 \\ = > x {}^{2} - 2x + 1 + x {}^{2} - 4x + 4 + x {}^{2} - 6x + 9 = 0 \\ = > 3x {}^{2} - 12x + 14 = 0$