(x+1)^2-x^2 has no real roots as it is not quadratic polynomial?
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Answered by
1
Answer:
no
Step-by-step explanation:
Answered by
1
Step-by-step explanation:
(x + 1)^{2} - {x}^{2}
(x + 1)(x + 1) - {x}^{2}
{x}^{2} + x + x + 1 - {x}^{2}
2x + 1
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