Question

(x-1)^2=x^3-1
find the no of real solutions

Answer 1

Answer:-

${(x - 1)}^{2} = {x}^{3} - 1$

${x}^{2} - 2 \times x \times + {1}^{2} = {x}^{3} - 1$

${x}^{2} - 2x +1 = {x}^{2} - x - 1$

${x}^{2} - {x}^{2} - 2x - + x = 1 + 1$

$- x = 2$

$x = -2$

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