(x-1)^2/x^3+x=A/x+Bx+c/x^2+1 then a,b,c
Answers
Answered by
2
Answer:
x
3
+x
(x+1)
2
=
x
A
+
x
2
+1
Bx+C
Consider,
x
3
+x
(x+1)
2
=
x(x
2
+1)
x
2
+2x+1
=
x
A
+
x
2
+1
Bx+C
x(x
2
+1)
x
2
+2x+1
=
x(x
2
+1)
A(x
2
+1)+x(Bx+C)
x(x
2
+1)
x
2
+2x+1
=
x(x
2
+1)
(A+B)x
2
+Cx+A
⇒x
2
+2x+1=(A+B)x
2
+Cx+A
by comparing the coefficients we get
⇒A=1,C=2,A+B=1
⇒sin
−1
(
C
A
)=sin
−1
(
2
1
)=
6
π
Hence, option 'A' is correct.
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SIMILAR QUESTIONS
star-struck
If
(x−2)(x−3)
3
1
=
x−2
A
+
x−3
B
+
(x−3)
2
C
+
(x−3)
3
D
then B=
Medium
View solution
>
If
(x−3)(x−2)
x
=
x−3
3
+
x−2
A
Answered by
1
Answer:
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