Math, asked by riskylathwal9271, 7 months ago

(x+1)²(x-5)=0 real roots of an equation

Answers

Answered by kesarwanipratham8077

3

(x^2+1+2x)(x-5)

x^3-5x^2+x-5-2x^2-10x

x^3-7x^2-9x-5

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