Math, asked by shubham26604, 8 months ago

(x+1)^2 +(x² +3x+2)^2 = 0

Answers

Answered by swastipandeyin
0

Step-by-step explanation:

(x+1)^2 +(x² +3x+2)^2 = 0

formula

(a+b)= a^2+b^2+2ab

x^2+1+2x+(x^2+2x+x+2)^2=0

x^2+1+2x+[{x(x+2)+(x+2)}]^2=0

x^2+1+2x+{(x+2)(x+1)}^2=0

(x+1)^2+(x+1)^2(x+2)^2=0

(x+1)^2{1+(x+2)^2}=0

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