(x+1)^2 +(x² +3x+2)^2 = 0
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Step-by-step explanation:
(x+1)^2 +(x² +3x+2)^2 = 0
formula
(a+b)= a^2+b^2+2ab
x^2+1+2x+(x^2+2x+x+2)^2=0
x^2+1+2x+[{x(x+2)+(x+2)}]^2=0
x^2+1+2x+{(x+2)(x+1)}^2=0
(x+1)^2+(x+1)^2(x+2)^2=0
(x+1)^2{1+(x+2)^2}=0
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