x-1)²+(y-1)²=0 find the value of x and y '
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Step-by-step explanation:
=>(x-1)²+(y-1)²=0
=>[(x- 1)+(y- 1)]²+2[(x-1)+(y-1)]=0
=>(x -1)+(y -1)+2=0
=>x+y - 2+2=0
=>x+y=0..... (i)
Again
=>(x -1)²+(y -1)²=0
=>x² - 2x + 1 + y² - 2y +1 = 0
=>x²+y²- 2(x+y) +2 = 0
=>x²+y²= -2..... (ii)
Now multiply equ (i ) with x and subtract from equ ... ( ii)
=>x²+ y²- x²-xy = -2-0
=>x - y = 2y.....( iii )
Adding equation ( i) and ( iii )
we get x= y
therefore when value of x will be Same as value of y will be Same.
formula s used here
(a+b)²= a²+2ab+b ²
=>a²+b²=(a+b)²–2ab
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