Question

x=1+√2,y=1-√2 find x²+y²=​

Answer 1

Answer:

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Answer 2

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Answer:

$( { x + y})^{2} = {x}^{2} + {y}^{2} + 2xy$

${x}^{2} + { y }^{2} + 2 \times (1 + \sqrt{2} )(1 - \sqrt{2}) = ( {1 + \sqrt{2} })^{2} + ( {1 - \sqrt{2} })^{2} + 2 \times (1 + \sqrt{2} )(1 - \sqrt{2})$

${x}^{2} + {y}^{2} + 2 - 4 = 1 + 4 + 2 \sqrt{2} + 1 + 4 - 2 \sqrt{2} + 2 - 4$

${x}^{2} + {y}^{2} = 10$