(x-1)²+(y-2)²=(x-1)(y-2)
then what is x³+y³
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Answer:
Solve for x
x-y=3
x=3+y
Now plug x into the second equation and solve for y.
x^3-y^3=9
(3+y)^3-y^3 =y
y^3+9y^2+27y+27-y^3=9
9y^2+27y+27=9
y^2+3y+3=1
y^2+3y+2=0
(y+1)(y+2)=0
y=-1; -2
Solve for x using these values and the x equation:
x=3+y
x= 3+(-1), x=3+(-2)
x=2, 1
Now, finally, plus the corresponding x and y values into x+y:
x+y
2+(-1), 1+(-2)
1, -1
So x+y has two possible values: 1 and -1.
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