Math, asked by anuroy1482, 10 months ago

(x-1)^2 + (y-2)^2+(z-3)^2+(a-4)^2=0, what is the value of (x+y+z+a)

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Answered by ashutosh414795

1

Step-by-step explanation:

(x-1)^2 + (y-2)^2+(z-3)^2+(a-4)^2=0, what is the value of (x+y+z+a)

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