Question

x+1=2logbase2(2^x+3)-2logbase4(1980-2^-x)
find the sum of solutions of this equation????​

Answer 1

Answer:

x+1= 2 log2( 2x+3) – 2 log4(1980 – 2-x )

Can be written as:

Now,

x+1 = log2( 2x+3)^2 – log2(1980 – 2-x )

x+1 = log2( (2x+3)^2) /(1980-2^x))

(2x+3)^2) /(1980-2^x) = 2^(x+1)

(2x+3)^2 = (1980-2^x)*2^x.2

take 2^x = t and solve the expression.