x-1÷2x+1+2x+1÷x-1=2 find the roots of the following question?
Answers
Answered by
2
(x-1)/(2x+1) +(2x+1)/(x-1)=2
=>{(x-1)^2+(2x+1)^2}/(x-1)(2x+1)=2
=>(x^2-2x+1+4x^2+4x+1)/(2x^2-x-1)=2
=> 5x^2+2x+2=4x^2-2x-2
=> x^2+4x+4=0
=>(x+2)^2=0
=> x=-2
=>{(x-1)^2+(2x+1)^2}/(x-1)(2x+1)=2
=>(x^2-2x+1+4x^2+4x+1)/(2x^2-x-1)=2
=> 5x^2+2x+2=4x^2-2x-2
=> x^2+4x+4=0
=>(x+2)^2=0
=> x=-2
DavidSuperior:
wrong answer
it is supposed to be 2
dear if you put x=2 then (2-1)/(2x2+1)+(2x2+1)/(2-1)> 2 not =2
thanks
Answered by
1
on solving , the roots come out to be -
x=-2 and x=-2 (both are same )
x=-2 and x=-2 (both are same )
please check again
ok
please correct your answer
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