Question

(x-1)^=2x+3 compare it to the general form and find the value of a b c​

Answer 1

Answer:

$(x - 1) {}^{2} = 2x + 3 \\ \\ {x}^{2} + 1 - 2x = 2x + 3 \\ \\ {x}^{2} + 4x - 2 = 0 \\ \\ compare \: a {x}^{2} + bx + c \\ \\ a=1 \\ \\ b = 4 \\ \\ c = - 2$

Answer 2

Answer:

$a=1,\:b=-4,\:c=-2$

Step-by-step explanation:

$Given \: quadratic\: equation:$

$(x-1)^{2}=2x+3$

$\implies x^{2}-2\times x\times 1+1^{2}=2x+3$

$\implies x^{2}-2x+1-2x-3=0$

$\implies x^{2}-4x-2=0$

$\implies 1x^{2}-4x-2=0\:compare \:this\\with \:ax^{2}+bx+c=0,we\:get$

$a=1,\:b=-4,\:c=-2$

Therefore,

$a=1,\:b=-4,\:c=-2$

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