Question

x(1+2x) = 528 , then find x​

Answer 1

Here Is Your Answer

x(1+2x) = 528

=> (x+2x^2) =528

=> 2x^2 + 2x -528 =0

=> 2x^2 + 33x -32x - 528 =0

=>x (2x+33) -16(2x+33) =0

=> (2x +33) (x-16)=0

Now ,

2x+33=0

=> x = 33/2

and

x-16=0

=> x = 16

Hope It Helped You

Answer 2

$\huge\blue{Answer:}$

x+2x²=528

2x²+x-528=0

2x²+33x-32x-528=0

x(2x+33)-16(2x+33)=0

(2x+33)(x-16)=0

x= 16,-33/2