Question

x=1/3+2√2 then find the value of x²+1/x²​

Answer 1

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if x= 2+sqrt3

then

1/x=2-sqrt3 (by rationaliztion)

then (x+1/x)^2 = X^2+(1/X)^2 +2*x*(1/X)

that is (2+sqrt3 +2-sqrt3)^2=x^2 +(1/x)^2+2

4^2 -2=x^2+(1/x)^2

i.e, 14 is the answer

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Answer 2

Answer:

If x= 2+sqrt3

then

1/x=2-sqrt3 (by rationaliztion)

then (x+1/x)^2 = X^2+(1/X)^2 +2*x*(1/X)

that is (2+sqrt3 +2-sqrt3)^2=x^2 +(1/x)^2+2

4^2 -2=x^2+(1/x)^2

i.e, 14 is the answer