Question

x - 1/3=2 find the value of x​

Answer 1

Answer:

x = 2 1/3

Step-by-step explanation:

If x - 1/3 = 2, we can find x by adding 1/3 to 2. 2 + 1/3 = 2 1/3.

Hence, the above answer.

Answer 2

Answer:

Required value of x is $2 \frac{1}{3}$

Step-by-step explanation:

Given,

$x - \frac{1}{3} = 2$

We want to solve this equation.

We are separating variable and constant part.

$x = 2 + \frac{1}{3}$

We are adding 2 and $\frac{1}{3}$

$x = \frac{2 \times 3 + 1}{3} \\ x = \frac{6 + 1}{3} \\ x = \frac{7}{3} \\ x = 2 \frac{1}{3}$

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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