Question

(x-1)^3+ 9(x^2-1) factorize​

Answer 1

Explanation:

${(x - 1)}^{3} + 9( {x}^{2} - 1) \\ {(x - 1)}^{3} \: : {x}^{3} - {3x}^{3} + 3x - 1 \\ = {x}^{3} - {3x}^{2} + 3x - 1 + 9( {x}^{2} - 1) \\ expand \: 9( {x}^{2} - 1): {9x}^{2} - 9 \\ = {x}^{3} - {3x}^{2} + 3x - 1 + {9x}^{2} - 9 \\ simplify \: {x}^{3} - {3x}^{2} + 3x - 1 + {9x}^{2} - 9: {x}^{3} \\ = {x}^{3} + {6x}^{2} + 3x - 10.$

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