Question

(x+1)3-(x-1)3 saral kare​

Answer 1

Answer:

=(3x+3)-3x+3

=3x-3x+3+3

=3+3

=6

Answer 2

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\sf \bf {(x+1)}^{3}-{(x-1)}^{3}$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf \implies {(x+1)}^{3}-{(x-1)}^{3}$

$\sf \bf \implies {x}^{3}+{1}^{3}+3 \times x \times 1(x+1) - [{x}^{3}-{1}^{3}-3 \times x \times 1(x-1)]$

$\sf \bf \implies {x}^{3}+1+3x (x+1) - [{x}^{3}-1-3x(x-1)]$

$\sf \bf \implies {x}^{3}+1+3{x}^{2}+3x- [{x}^{3}-1-3{x}^{2}+3x]$

$\sf \bf \implies {x}^{3}+1+3{x}^{2}+3x- {x}^{3}+1+3{x}^{2}-3x$

$\sf \bf \implies \cancel {{x}^{3}} +1+3{x}^{2} \cancel {+3x} \cancel {- {x}^{3}} +1+3{x}^{2} \cancel {-3x}$

$\sf \bf \implies 1+3{x}^{2}+1+3{x}^{2}$

$\implies{\boxed {\boxed {\sf \bf 2+6{x}^{2}}}}$

$\sf \bf {Used\:Formulas}$

$\sf \bf \implies {(a+b)}^{3}={a}^{3}+{b}^{3}+3ab(a+b)$

$\sf \bf \implies {(a-b)}^{3}={a}^{3}-{b}^{3}-3ab(a-b)$

$\sf \bf \huge {\boxed {\mathbb {HOPE\:IT \:HELPS \:YOU}}}$

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$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\sf \bf {Identities}$

$\sf \bf \implies {(a+b)}^{3}={a}^{3}+{b}^{3}+3ab(a+b)$

$\sf \bf \implies {(a-b)}^{3}={a}^{3}-{b}^{3}-3ab(a-b)$

$\sf \bf {a}^{3}+{b}^{3}=(a+b) ({a}^{2}+{b}^{2}-ab)$

$\sf \bf {a}^{3}-{b}^{3}=(a-b) ({a}^{2}+{b}^{2}+ab)$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5070}}}}}}}}}}}}}}}$