Math, asked by Krishna8244, 9 months ago

(x-1)^3(x-2)^5(x+3)^6 less than or equal to zero

I want this in interval notation

Answers

Answered by sagayrajsagaya
0

Answer:

x-1)^3(x-2)^5(x+3)^6 less than or equal to zero

Step-by-step explanation:

2/22

2^3®4>

2 >

2 ^

Answered by AlluringNightingale
0

Answer:

x € [ 1 , 2 ] U { –3 }

Solution:

Here ,

We need to find the solution set for the given inequation ;

(x - 1)^3(x - 2)^5(x + 3)^6 ≤ 0.

If x - 1 =.0

then x = 1

If x - 2 = 0

then x = 2

If x + 3 = 0

then x = -3

Thus,

The critical points are : x = -3 , 1 , 2

Now,

The sign scheme for the given inequation will be ;

+ + – +

-∞ <-------(-3)--------( 1 )--------( 2 )--------> ∞

Thus,

The required solution set will be given as ;

x € [ 1 , 2 ] U { –3 }

Hence,

x € [ 1 , 2 ] U { 3 }

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