Question

x+1/3 -x-6/2=x/2
step wise explanation​​

Answer 1

Answer:

Value of x is -16/3

Step-by-step explanation:

Question:-

$x + \frac{1}{3} - x - \frac{6}{2} = \frac{x}{2}$

Solution:-

First we have cancelling the -6/2 with 2

So cancelling with two we get,

$x + \frac{1}{3} - x - 3 = \frac{x}{2}$

Combining like terms,

$x - x + \frac{1}{3} - 3 = \frac{x}{2}$

As 1/3 and -3 having different denominators we need to take lcm,

Lcm=3

$x - x + \frac{1}{3} - \frac{9}{3} = \frac{x}{2}$

$- \frac{8}{3} = \frac{x}{2}$

$- \frac{8}{3} \times 2 = x$

$- \frac{16}{3} = x$

Therefore value of x is -16/3

Answer 2

Given :

An equation $x+\frac{1}{3} -x-\frac{6}{2} =\frac{x}{2}$.

To find :

The value of x.

Step-by-step explanation:

• The value of x can be found by following these steps.
• The given equation is

        $x+\frac{1}{3} -x-\frac{6}{2} =\frac{x}{2}$

• Keep the variables on one side and the numbers to the other side.
• Then the equation will be

         $x-x-\frac{x}{2} =\frac{6}{2} -\frac{1}{3}$

• Cancel out the unlike terms.
• Then the equation will become

        $-\frac{x}{2} =3-\frac{1}{3}$

• Take the negative sign out

• Then the equation will arrive as      

         $\frac{x}{2} =\frac{1}{3} -3$

• Take the LCM on right side of the equation

         $\frac{x}{2} =\frac{1-9}{3}$

• Subtract the numbers

         $\frac{x}{2} =\frac{-8}{3}$

• Cross multiply the terms.

        $x=\frac{-8(2)}{3}$

• Multiply the numbers

        $x=\frac{-16}{3}$

• Divide the numerator and denominator

        $x=-5.3$

Final answer :

The value of $x$ is $-5.3$.