(X+1), 3x and(4x+2) are the first 3 terms of ap then x =?
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Given ,
1st term = ( x + 1 )
2nd term = 3x
3rd term = ( 4x + 2 )
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→ 2nd term - 1st term = 3x - ( x + 1 )
= 3x - x - 1
= 2x - 1
→ 3rd term - 2nd term = 4x + 2 - 3x
= x + 2
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These two differences are same because common difference is the same .
→ 2x -1 = x + 2
→ 2x -x = 2 + 1
→ x = 3
The three terms of the a.p. are 4 , 9 and 14 .
HOPE IT HELPS U ........... :)
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