Question

x+1 ÷3x cube + 3x square +3x+1
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Answer 1

Answer:

x+1+9x*5+9x*4+3x³=0

9x*5+9x*4+3x³+x+1=0

9x*5+9x*4+3x³+x=-1

x(9x*4+9x³+3x²+1)=-1

x=-1

9x*4+9x³+3x²+1=0

x²(9x²+9x+3)+1=0

x±1=0

9x²+9x+3=0

3(3x²+3x+1)=0

3x²+3x+1=0

use formula method u get urs answer perfectly