(x-1)^4+(x-5)^4=82
solve for x.
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(x-1) 4+(x-5) 4=82
(x square 5) 4=82
(xsq 5). 2=41
(x square 5) 4=82
(xsq 5). 2=41
krish602:
is that satisfying equation
Answered by
1
Answer:this have 2 real and 2 imaginary roots
Step-by-step explanation:
By solving the equation (x-1)^4+(x-5)^4,
You will get x^4-12x^3+78x^2-25x+272=0
So now, we have to get this equation in terms of ax^2+bc+c=0 to solve it....
Now, we have to divide this equation with something ...
Divide this with "x^2-2x-8" which is (x+2)(x-4)
You will get it terms of ax^2+bx+c =0
Now,...solve the quadratic equation
Formulae- (-b(plus or minus )√b^2-4ac)/2a
Hope this helped you
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