X=1/4 y=3/2 find (x+y) ÷(x-y) if
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Answer:
x=
4
1
and,
y =\frac{3}{2}y=
2
3
To find:
The value of \frac{x+y}{x-y}
x−y
x+y
= ?
Solution:
⇒ \frac{x+y}{x-y} =\frac{\frac{1}{4} +\frac{3}{2} }{\frac{1}{4} -\frac{3}{2} }
x−y
x+y
=
4
1
−
2
3
4
1
+
2
3
By taking L.C.M, we get
=\frac{\frac{1+6}{4} }{\frac{1-6}{4} }=
4
1−6
4
1+6
=\frac{1+6}{1-6}=
1−6
1+6
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