x+1/4x = 3/2, find 8x³ + 1/8x³
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Answer:
243.
Solution is as follows:
The desired difference looks like (a^3) - (b^3) with a = (3x) and b = (1/2x).
The first equation (2x) - (1/3x) looks like (a - b) but the terms seem different. To get (3x) - (1/2x) from first equation we can multiply the first equation on both sides by (3/2):
(3/2)[(2x) - (1/3x)] = (3/2) * 4
=> (3x) - (1/2x) = 6
Now that we have (a - b), we can compute (a^3) - (b^3) using the identity:
(a^3) - (b^3) = (a - b)(a^2 + ab + b^2) = A * B
Step-by-step explanation:
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