Question

{(x+1) (4x-3) -4x^2+5}/4x+1 =2​

Answer 1

Step-by-step explanation:

$\frac{( x+ 1)(4x - 3) - 4 {x}^{2} + 5}{4x + 1} = 2$

$x(4x - 3) + 1(4 x - 3) - 4{x}^{2} + 5 = 2(4x + 1)$

$4 {x}^{2} - 3x + 4x - 3 - 4{x}^{2} + 5 = 8x + 2$

$x + 2 = 8x + 2$

$2 - 2 = 8x - x$

$0 = 7x$

$x = 0$