(x+1)(4x-3)-4x^ +5 /4+1=2 from linear equations in one va
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Let's solve your equation step-by-step.
(x+1)(4x−3)−
4x5
4
+1=2
−x5+4x2+x−2=2
Step 1: Subtract 2 from both sides.
−x5+4x2+x−2−2=2−2
−x5+4x2+x−4=0
Step 2: Factor left side of equation.
(−x−1)(x−1)(x3+x−4)=0
Step 3: Set factors equal to 0.
−x−1=0 or x−1=0 or x3+x−4=0
x=−1 or x=1 or x=1.378797
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