Question

X^1/a=Y^1/b=Z^1/c and xyz=1 then prove
a+b+c=0 procces also

Answer 1

Assume a=p and b= q and c= r
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Answer 2

Answer:

Step-by-step explanation:

x^1/a=y^1/b=z^1/c=k (let)

x=k^a

y=k^b

z=k^c

xyz=k^ak^bk^c=k^(a+b+c)

or,1=k^(a+b+c)

or, k^0=k^(a+b+c);k≠0

or, a+b+c=0

Hence prove.