(x-1) and (x-2) are the factors of the polynomial x³-ax²- bx-4. Find the value of a and b
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There are many methods to solve this problem. Either u can multiply factors and divide dividend by resultant to get quotient = constant value. or use my easy method.
f(1)=1-a-b-4=0
-a-b=3
therefore a+b=-3 ---1
f(2)=8-4a-2b-4=0
-4a-2b=-4
2a+b=2 ---2
subtract the eqs.
a=5
b=2-2a
=2-10
=-8
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