Question

x=1 and y=-1 Questions 3x²+3y²-3xy
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Answer 1

Answer:

9

Step-by-step explanation:

3x²+3y²-3xy= 3(1²)+3(-1²)-3(1)(-1)

=3(1) +3(1) - 3 (-1)

=3+3+3

=9

Answer 2

Answer:

∴ The value of equation $3x^{2} +3y^{2} -3xy$ at  $x=1$ and $y=-1$ is $9$.

Step-by-step explanation:

In context to question asked,

• We have to find the value of equation $3x^{2} +3y^{2} -3xy$ at $x=1$ and $y=-1$.
• To find the value of given equation, put  $x=1$ and $y=-1$ in the equation.
• We know that, in a multiplication, square of any negative number is positive number.
• In Multiplication, -ve*+ve=-ve and -ve*-ve=+ve.
• So, the given equation is,

        $3x^{2} +3y^{2} -3xy$

• Put  $x=1$ and $y=-1$ in above equation, we get

        $3x^{2} +3y^{2} -3xy = 3(1\times1)+3(-1\times-1)-3\times1\times(-1)$

                              = $3\times1+3\times+3\times1$

                              = $3+3+3$

                              = $9$

• ∴ The value of equation $3x^{2} +3y^{2} -3xy$ at  $x=1$ and $y=-1$ is $9$.