x+1 ➗ by 3x²+2x¹ with solution
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Answered by
1
Step-by-step explanation:
- Given polynomial p(x)=ax
- 3
- +3x
- 2
- −13 and 2x
- 2
- −5x+a is divided by x-2 get same remainder
- Then x-2=0 or x=2
- p(x)=ax
- 3
- +3x
- 2
- −13
- Replace x by 2 we get
- p(2)=a(2)
- 3
- +3(2)
- 2
- −13
- ⇒p(2)=8a+12−13
- ⇒p(2)=8a−1
- 2x
- 2
- −5x+a
- Replace x by 2 we get
- q(2)=2(2)
- 3
- −5(2)+a
- ⇒q(2)=16−10+a
- ⇒q(2)=6+a
- Given remainder is same
- ∴8a−1=6+a
- ⇒8a−1+1−a=6+a+1−a
- ⇒7a=7
- a=1
Answered by
1
Step-by-step explanation:
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