x+1 by x=3,find value of x^4+1 by x^4
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please refer the attachment
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Anonymous:
please I thought x+1 is divided by x
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Given Equation is x + (1/x) = 3.
On squaring both sides, we get
⇒ (x + 1/x)^2 = (3)^2
⇒ x^2 + 1/x^2 + 2 = 9
⇒ x^2 + 1/x^2 = 9 - 2
⇒ x^2 + 1/x^2 = 7.
On squaring both sides, we get
⇒ (x^2 + 1/x^2)^2 = (7)^2
⇒ x^4 + 1/x^4 + 2 * x^2 * 1/x^2 = 49
⇒ x^4 + 1/x^4 + 2 = 49
⇒ x^4 + 1/x^4 = 49 - 2
⇒ x^4 + 1/x^4 = 47.
Hope it helps!
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