X + 1 by x = 3 find x square + 1 by x squared and x cube + 1 by xq
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i cant get right ideo on this question sorry
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Answer:
Let x/a = y/b = z/c = k, [By k method]
x = ak, y= bk and z=ck
L.H.S. = a3k3/a2 + b3k3/b2 + c3k3/c2 > k3[a + b + c]
R.H.S. = [ak + bk + ck]3/[a + b + c)2 → k3[a + b + c]3/[a + b + c)2
= k3(a + b + c)
L.H.S. = R.H.S. =
Hence proved.
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