x+1 by xcube+3xsquare+3x+1 long division method
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by remainder theorem
x+1=0
x=−1
p(x)=x 3+3x 2 −3x−1p(−1)
=(−1) 3 +3(−1) 2 −3(−1)−1
=−1+3(1)+3−1
=−1+3+3−1
=6−2
=4
Thus remainder is 4
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