(x + 1)cube – (x - 1)cube
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2
Answer:
(x+1+x-1){(x+1)^2+(x-1)^2-(x+1)(x-1)}
2x{x^2+1+2x+x^2+1-2x-(x^2-1^2)}
2x{x^2+1+2x+x^2+1-2x-x^2+1}
2x{x^2+3}
is your answer
zeroes is
2x=0 or x^2+3=0
x=0,1/√3
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Answer:
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