X 1 gram of an element gives x2 gram of its oxide the equivalent mass of element is
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Hey mate here is your answer...
hey A1 and A2 = Solution
Dear student!
The exact weight could not be calculated as data is not given, however it may be solved as:
Weight of metal = x gm
Weight of oxide = y gm
Oxygen consumed = y-x gm
Since, (y-x) gm of oxygen combines with x gm of metal
So, 1 gm of oxygen will combine with = x/ (y-x) gm of metal
Hence, 8 gm of oxygen will combine with = 8x/ (y-x) gm of metal
This 8x/(x-y) quantity is the equivalent weight of metal.
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