Question

x-1>√x-1, how to solve this?​

Answer 1

Step-by-step explanation:

We know, for all $y\in\:R-(-1,1)$, $y^2\:>\:y$

Put $y=(x-1)$

So,

$(x - 1)^{2} > (x - 1)$

$\implies \sqrt{(x - 1)^{2} }> \sqrt{(x - 1)}$

$\implies (x - 1)> \sqrt{(x - 1)}$

Answer 2

Answer:

Refer the attachment .

Hope it will help you army