Question

(X+1) is a factor of 2n^3-8n^2+3n+k find k
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Answer 1

Answer:

p(x)=2x³-8x²+3x+k

(x+1) =0

x=-1

p(-1)=2(-1)³-8(-1)²+3(-1)+k=0

2(-1)-8(1)-3+k=0 [(-1)³=(-1); (-1)²=(1)]

-2+8-3+k=0

3+k=0

k=-3

Answer 2

Answer:

(x+1) =0

x=-1

Then, 2(-1)³-8(-1)²+3(-1)+k=0

-2-8-3+k=0

k-13=0

k=13 . Ans

Step-by-step explanation:

k=13 is your correct answer.

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