Question

(x+1) is a factor of (2x square + kx) find k

Answer 1

Here is your answer
When k = 2 (x+1) is a factor of (2x^2+kx)

Answer 2

The value of k=2

p(x)=2x square+kx

Factor of p(x) is (x+1)

therefore, zero of p(x)=(-1)

p(-1)=2(-1)square+ k(-1)=0

2-k=0

-k=-2

k=2