Question

(x-1) is a factor of following polynomial

(a) x^12 - 1
(b) x^2020 - 1
(c) 4x^3 + 3x^2 + 5x - 12
(d) all

with step by step explaination
don't post irrelevant questions. ​

Answer 1

Answer:

see below

Step-by-step explanation:

(a) , (b) is a factor

because (a) 1 ^12-1 =0

(b) 1^2020 - 1=0

hope it helps you

Answer 2

Answer:

$(x - 1) \: \: \: \: \: take \: \: \: x = 1 \\ a) x {}^{12} - 1 = 1 - 1 = 0 \: \: \: \\ b)x {}^{2020 } - 1 = 1 - 1 = 0 \\c)4x {}^{3} + 3x {}^{2} + 5x - 12 = 4 + 3 + 5 - 12 = 0 \\ so \: \: all \: \: are \: \: \: factors \: \: \: of \: \: (x - 1) \\ answer \: \: is \: \: \: option \: \: \: d)all$

Hope it will help you.