(x-1) is a factor of polynomial f(x) but not off g(x) then it must be a factor of a.f(x) g(x) b.f(x) - g(x) c. f(x)-g(x)
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Answer. As (X-1) is a factor of polynomial f(x), it means it can be divided by (x-1) and it leaves no remainder. Now in case of f(x)g(x), it will again get divided and will leave no remainder as X-1 is a factor of f(x).
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I don't no ok bye how r u ok bye ha ha ha
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