Question

(x – 1) is a factor of the polynomial p(x)=3x4 – 4x3 – ax + 2 then

the value of ‘a’.​

Answer 1

Answer:

Value of a = 1

Step-by-step explanation:

$\tt \bold \red{༒︎To Fɪɴᴅ:-}$

• p(x)=3x^4 – 4x^3 – ax + 2

$\tt \bold \red{༒︎Given:-}$

• (x – 1) is a factor of the polynomial p(x)=3x4 – 4x3 – ax + 2

First we have to find value of x ,

$\tt \to x - 1 = 0 \\ \tt \to x = 1$

Now put the value of x to find the value of a,

$\tt \to3 \times( {1})^{4} - 4 \times {1}^{3} - a \times 1 + 2 = 0 \\ \tt \to3 \times 1 - 4 \times 1 - a + 2 = 0 \\ \tt \to3 - 4 + 2 - a = 0 \\ \tt \to1 - a = 0 \\ \tt \to - a = - 1 \\ \tt \red{ \to a = 1}$

_______________________________________

❀Tʜᴀɴᴋs ғᴏʀ ǫᴜᴇsᴛɪᴏɴ❀

Answer 2

Answer:

Value of a = 1

Step-by-step explanation:

$\tt \bold \red{༒︎To Fɪɴᴅ:-}$

p(x)=3x^4 – 4x^3 – ax + 2

$\tt \bold \red{༒︎Given:-}$

(x – 1) is a factor of the polynomial p(x)=3x4 – 4x3 – ax + 2

First we have to find value of x ,

$\begin{gathered} \tt \to x - 1 = 0 \\ \tt \to x = 1\end{gathered}$

Now put the value of x to find the value of a,

$\begin{gathered} \tt \to3 \times( {1})^{4} - 4 \times {1}^{3} - a \times 1 + 2 = 0 \\ \tt \to3 \times 1 - 4 \times 1 - a + 2 = 0 \\ \tt \to3 - 4 + 2 - a = 0 \\ \tt \to1 - a = 0 \\ \tt \to - a = - 1 \\ \tt \red{ \to a = 1}\end{gathered}$

______________________________________

❀Tʜᴀɴᴋs ғᴏʀ ǫᴜᴇsᴛɪᴏɴ❀